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Run-time Error '13' Type Mismatch | Rate this: (2.2/5 from 4 votes) |
| I read the previous post in the forum to check data type when this occurs. All of the data is clearly numerical and should not be the problem. I am working with about 14,000 observarations and keep getting this error. Is it because there are to many observations? There is no difference in the number of observations per variable so this is also not the problem. Please let me know how to fix this. | ||
| Posted by Payers24 on | ||
| Replies - Displaying 11 to 13 of 13 | Order Replies By: Most Recent | Chronological | Highest Rated |
Rate this: (3/5 from 1 vote) We have updated the download version to check for missing variable data in order to resolve this issue. | |
| Excel Business Forums Administrator | |
| Posted by Excel Helper on |
Rate this: (3/5 from 1 vote) Any ideas? Could it relate somehow to the small sample size? | |
| Steve | |
| Posted by edxmd on |
Rate this: (3/5 from 1 vote) When I do that thats when i get the mismatch Error, Please assist, here is my code Sub Macro1() Dim strPassword, Part1, Part2, Part3 As String Dim xPos As String Dim xLen As Integer ' Range("A1").Select strPassword = Range("A1").Value xLen = Len(strPassword) xPos = xLen / 2 If xLen Mod 2 <> 1 Then Part1 = Mid(strPassword, xPos + 1, xPos) Part2 = "" Part3 = Mid(strPassword, 1, xPos) Else Part1 = Mid(strPassword, xPos + 2, xPos) Part2 = Mid(strPassword, xPos + 1, 1) Part3 = Mid(strPassword, 1, xPos) End If outstring = Part1 + Part2 + Part3 Range("D1") = outstring End Sub | |
| Posted by Hillary on |
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